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NEW QUESTION: 1
Which statement is true about page maximizer technology withJetIntelligence?
A. it includes an automatic seal remover.
B. It is based on intelligent modeling, providing more room for toner
C. It is supplied with the most current workgroup printers from this year's line-up
D. It securely authenticates the type of cartridge installed.
Answer: B
Explanation:
http://www8.hp.com/us/en/hp-news/pressrelease.html?id=1923205#.V4YCQGh97IU

NEW QUESTION: 2
Your customer wants to use specific combinations of average objective and competency rating as the overall performance rating. How do you set this up?
There are 3 correct answers to this question.
Response:
A. Turn on the OCOC rating in the Performance Form template XML.
B. Turn on the Friendly's method of rating in provisioning.
C. Remove the summary section from the Performance Form template XML.
D. Insert the specific mapping scale in the Objective /competency section.
E. Insert the specific mapping scale in the Meta section of Performance Form template XML.
Answer: A,D,E

NEW QUESTION: 3
Which will declare a method that forces a subclass to implement it?
A. Protected void methoda (double d1){}
B. Public double methoda();
C. Public native double methoda();
D. Static void methoda (double d1) {}
E. Abstract public void methoda();
Answer: E

NEW QUESTION: 4
Your company has a remote office that contains 600 client computers on a single subnet.
You need to select a subnet mask for the network that will support all of the client computers.
The solution must minimize the number of unused addresses.
Which subnet mask should you select?
A. 255.255.255.0
B. 255.255.254.0
C. 255.255.255.128
D. 255.255.252.0
Answer: D
Explanation:
255.255.252.0 = 11111111.11111111.11111100.00000000 => ( 22 bits 1 .. 10 bits 0 ) => 1111111111 = 1023
255.255.254.0 = 11111111.11111111.11111110.00000000 => ( 23 bits 1 .. 9 bits
0 ) => 111111111 = 511 255.255.255.0 = 11111111.11111111.11111111.00000000 => ( 24 bits 1 .. 0 ) => 11111111 = 255 255.255.255.128 = 11111111.11111111.11111111.10000000 => ( 25 bits 1 .. 0 ) => 1111111 = 127
8 bits 7 bits
http://zeus.fh-brandenburg.de/~ihno/doc/lehre/internet/ip_eng.html