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NEW QUESTION: 1
Identify the four valid IPv6 addresses. (Choose four.)
A. ::192:168:0:1
B. 2002:c0a8:101::42
C. 2001:3452:4952:2837::
D. 2003: deaD. beef:4dad:23:46:bB. 101
E. ::
F. 2000::
Answer: A,B,D,E
Explanation:
IPv6 addresses are normally written as eight groups of four hexadecimal digits, where each group is separated by a colon (:). For example, 2001:0db8:85a3:0000:0000:8a2e:0370:7334 is a valid IPv6 address. To shorten the writing and presentation of addresses, several simplifications to the notation are permitted. Any leading zeros in a group may be omitted; thus, the given example becomes 2001:db8:85a3:0:0:8a2e:370:7334 One or any number of consecutive groups of 0 value may be replaced with two colons (::): 2001:db8:85a3::8a2e:370:7334 This substitution with double-colon may be performed only once in an address, because multiple occurrences would lead to ambiguity. For example, the illegal address notation 2001::FFD3::57ab,
could represent
2001:0:0:0:0:FFD3:0:57ab
2001:0:0:0:FFD3:0:0:57ab
2001:0:0:FFD3:0:0:0:57ab and
2001:0:FFD3:0:0:0:0:57ab
Using the double-colon reduction the localhost (loopback) address, fully written as
0000:0000:0000:0000:0000:0000:0000:0001, may be reduced to ::1 and the undetermined IPv6
address (zero value), i.e., all bits are zero, is simply ::.
For example, the addresses below are all valid and equivalent:
2001:0db8:0000:0000:0000:0000:1428:57ab
2001:0db8:0000:0000:0000::1428:57ab
2001:0db8:0:0:0:0:1428:57ab
2001:0db8:0:0::1428:57ab
2001:0db8::1428:57ab
2001:db8::1428:57ab

NEW QUESTION: 2
A company is launching an application that it expects to be very popular. The company needs a database that can scale with the rest of the application. The schema will change frequently. The application cannot afford any downtime for database changes.
Which AWS service allows the company to achieve these objectives?
A. Amazon RDS MySQL
B. Amazon Aurora
C. Amazon Redshift
D. Amazon DynamoDB
Answer: D

NEW QUESTION: 3
すべての子会社は、親会社と同じ元帳を共有でき、すべて同じアプリケーションインスタンスに存在します。
彼らは会社間会計を実行します。統合を実行するためのオラクルの推奨アプローチは何ですか？
A. このタイプの複雑な統合にはOracle Hyperion FinancialManagementを使用します
B. 総勘定元帳の財務報告機能を使用して、各レポートが異なる子会社を表すセグメントのバランスをとることにより、連結レポートを作成します。消去エントリは、さらに別の個別のバランシングセグメントに入力できます
C. 統合のために複数の元帳を定義し、元帳セットについてレポートします
D. 総勘定元帳の残高転送プログラムを使用して、補助元帳の残高を親元帳に転送してから、消去エントリを親元帳の個別の貸借一致セグメントとして入力します。
Answer: B

NEW QUESTION: 4
When you create a refurbishment order, which reference objects can you use? (Choose three)
A. Material with serial number
B. Material without serial number
C. Functional location
D. Equipment with serial number
E. Equipment without serial number
Answer: A,B,D