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NEW QUESTION: 1
IPSアラートを調査し、それらの多くが通常のネットワークアクティビティによって生成されていることを発見しています。この状況の原因は何でしょうか？
A. プロアクティブな制御は制限が強すぎます。
B. リアクティブコントロールは具体的すぎます。
C. すべてのIPSシグニチャには、Produce Alertアクションが割り当てられています。
D. IPSは無差別モードで実行されています。
Answer: A

NEW QUESTION: 2
質問をドラッグアンドドロップ
IPv4ネットワークサブネットを左側から右側の正しい使用可能なホスト範囲にドラッグアンドドロップします

Answer:
Explanation:

Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111
1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is
172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet.
Therefore the last usable host is 172.28.229.254.

NEW QUESTION: 3



A. 10.0.0.0
B. 192.168.2.0
C. 172.16.4.0
D. 10.4.3.0
E. 192.168.0.0
F. 172.16.0.0
Answer: B,C,F

NEW QUESTION: 4
Data access security related to applications may be enforced through all of the following except:
A. Utility software functions.
B. Security functions provided by a database management system.
C. User identification and authentication functions incorporated in the application.
D. User identification and authentication functions in access control software.
Answer: A
Explanation:
Utility programs perform routine functions e.g.. sorting and copying), are available to all users, and are promptly available for many different applications. Utility programs are one of the more serious weaknesses in data access security because some can bypass normal access controls.