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NEW QUESTION: 1
Which aggregate of the IPv6 addresses 2001:0303:0000:5000:0000:052B:0000:0000/96 and 2001:0303:0000:5000:0000:052C:0000:0000/96 has the longest possible mask?
A. 2001:0303:0000:5000:0000:0528:0000:0000/93
B. 2001:0303:0000:5000:0000:052A:0000:0000/96
C. 2001:0303:0000:5000:0000:0520:0000:0000/92
D. 2001:0303:0000:5000:0000:052A:0000:0000/95
Answer: A

NEW QUESTION: 2

A. 172.19.20.16
B. 172.19.20.32
C. 172.19.20.0
D. 172.19.20.15
E. 172.19.20.20
Answer: A
Explanation:
Explanation
From the /28 we can get the following:
Increment: 16 (/28 = 11111111.11111111.11111111.11110000)
Network address: 172.19.20.16 (because 16 < 23)
Broadcast address: 172.16.20.31 (because 31 = 16 + 16 - 1)

NEW QUESTION: 3

A. Encryption
B. Replication
C. Real-time Compression
D. Virtualization
Answer: B