Medical Professional CCM Q&A - in .pdf

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NEW QUESTION: 1
Click the Exhibit button.
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:<1.1.1.100/51303->1.1.1.30/3389;6> matched filter MatchTraffic:
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:packet [48] ipid = 5015, @423d7e9e Feb 2
09:00:02 09:00:00.1872004:CID-0:RT:---- flow_process_pkt: (thd 1): flow_ctxt type 13, common flag Ox0, mbuf Ox423d7d00
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: flow process pak fast ifl 72
In_ifp fe-0/0/7.0
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: fe-0/0/7.0:1.1.1.100/51303- >1.1.1.30/3389, top, flag 2 syn
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: find flow: table Ox5258d7b0, hash
17008(Oxffff), sa 1.1.1.100, da 1.1.1.30, sp 51303, dp 3389, proto 6, tok
448
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: no session found, start first path. in_tunnel - 0, from_cp_flag - 0
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: flow_first_create_session
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: flow first_in_dst_nat: in <fe-0/0/7.0>, out
< N/A> dst_adr 1.1.1.30, sp 51303, dp 3389
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: chose interface fe-0/0/7.0 as incoming nat if.
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:flow_first_rule_dst_xlate: packet 1.1.1.100-
> 1.1.1.30 nsp2 0.0.0.0->192.168.224.30.
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:flow_first_routing: call flow_route_lookup() src_ip 1.1.1.100, x_dst_ip 192.168.224.30, in ifp fe-0/0/7.0, out ifp N/A sp 51303, dp 3389, ip_proto 6, tos 0
Feb 2 09:00:02 09:00:00.1872004:CID-O:RT:Doing DESTINATION addr route-lookup Feb
2 09:00:02 09:00:00.1872004:CID-0:RT: routed (x_dst_ip 192 168.224.30)
from untrust (fe-0/0/7.0 in 0) to ge-0/0/0.0, Next-hop: 192.168.224.30
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: policy search from zone untrust-> zone trust
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: policy has timeout 900
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: app 0, timeout 1800s, curr ageout 20s
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:flow_first_src_xlate: src nat 0.0.0.0(51303) to
192.168.224.30(3389) returns status 1, rule/pool id 1/2. Feb 2 09:00:02
09:00:00.1872004:CID-0:RT: dip id = 2/0, 1.1.1.100/51303->192.168.224.3/48810
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: choose interface ge-0/0/0.0 as outgoing phy if
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:is_loop_pak: No loop: on ifp: ge-0/0/0.0, addr:
192.168.224.30, rtt_idx:0
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:sm_flow_interest_check: app_id 0, policy 9, app_svc_en 0, flags Ox2. not interested
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:sm_flow_interest_check: app_id 1, policy 9, app_svc_en 0, flags Ox2. not interested
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT:flow_first_service_lookup():
natp(Ox51ee4680): app_id, 0(0).
Feb 2 09:00:02 09:00:00.1872004:CID-0:RT: service lookup identified service O.
Referring to the exhibit, which two statements are correct? (Choose two.)
A. Source NAT is being used.
B. The packet being inspected is a UDP packet.
C. This traffic matches an existing flow.
D. The incoming interface is fe-0/0/7.
Answer: C,D

NEW QUESTION: 2
Chandler works as a pen-tester in an IT-firm in New York. As a part of detecting viruses in the systems, he uses a detection method where the anti-virus executes the malicious codes on a virtual machine to simulate CPU and memory activities. Which type of virus detection method did Chandler use in this context?
A. Scanning
B. Integrity checking
C. Code Emulation
D. Heuristic Analysis
Answer: C

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
#include <deque>
#include <iostream>
#include <algorithm>
#include <set>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};
deque<int> d1(t, t+10);
set<int> s1(t,t+10);
cout<<binary_search(s1.begin(),s1.end(), 4)<<" "<<binary_search(d1.begin(),d1.end(),
4 )<<endl;
return 0;
}
Choose all possible outputs (all that apply):
A. true true
B. false false
C. compilation error
D. 1 1
E. 1 0
Answer: D,E

NEW QUESTION: 4





A. GROUP BY ROLLUP
B. GROUP BY CUBE
C. MERGE
D. CROSS JOIN
E. PIVOT
F. LEFT JOIN
G. GROUP BY
H. UNPIVOT
Answer: B
Explanation:
Explanation
Example of GROUP BY CUBE result set:
In the following example, the CUBE operator returns a result set that has one grouping for all possible combinations of columns in the CUBE list and a grand total grouping.

References: https://technet.microsoft.com/en-us/library/bb522495(v=sql.105).aspx

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