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NEW QUESTION: 1
You are the program manager for your organization. This program will last for two years and has eight projects. The cost of your program is $4 million and there are some risk concerns that may affect the overall cost of the program. Management is concerned with how long it will take the program to reach the management horizon. What is management horizon also known as?
A. Cost performance index
B. Return on investment
C. Cost-to-benefits ratio
D. Payback period
Answer: D

NEW QUESTION: 2
VPC 용 인터넷 연결을 설계하고 있습니다. 웹 서버는 인터넷에서 사용할 수 있어야합니다. 응용 프로그램에는 고 가용성 아키텍처가 있어야합니다.
어떤 대안을 고려해야 합니까? (2 답 선택)
A. 모든 웹 서버를 ELB 뒤에 배치합니다. Route53 CNMIE가 ELB DNS 이름을 가리 키도록 구성합니다.
B. EIP로 ELB 구성 모든 웹 서버를 ELB 뒤에 배치 EIP를 가리키는 Route53 A 레코드를 구성합니다.
C. CloudFront 배포를 구성하고 웹 서버의 개인 IP 주소를 가리 키도록 원본을 구성합니다. CloudFront 배포에 대한 Route53 CNAME 레코드를 구성합니다.
D. VPC에서 NAT 인스턴스 구성 NAT 인스턴스를 통해 기본 경로를 만들고 모든 서브넷과 연결합니다. NAT 인스턴스 공용 IP 주소를 가리키는 DNS A 레코드를 구성합니다.
E. 모든 웹 서버에 EIP를 할당합니다. 모든 EIP로 구성된 Route53 레코드 세트를 구성하십시오. 상태 확인 및 DNS 장애 조치.
Answer: A,C

NEW QUESTION: 3
10.0.0.0/24サブネット内の奇数番号のホストから許可される標準のアクセス制御エントリはどれですか。
A. 許可10.0.0.1.0.0.0.0
B. 許可10.0.0.0.0.0.0.1
C. 許可10.0.0.1.0.0.0.254
D. 許可10.0.0.0.255.255.255.254
Answer: C
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.

NEW QUESTION: 4
A technician is working on a Linux VM in a lab environment to become more familiar with the operating system. The technician has configured a basic website and wants to allow access to it different machine on the local network. Which of the following should the technician do so other machines can connect?
A. Use netslat to open necessary ports
B. Add access rules in iptables
C. Employ arp lo configure a new route
D. Allow communication through ifconfig
Answer: A