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NEW QUESTION: 1
Which of the following options best describes the differences between a traditional data warehouse environment and a Hadoop environment?
A. Typically, data stored in Hadoop environments is cleaned up before storing in the distributed
file-system.
B. Typically, data stored in data warehousing environments is rarely filtered and pre-processed.
On the other hand, data injected into Hadoop
environments is always pre-processed and filtered.
C. Hadoop environments are mostly ideal for analyzing structured and semi-structured data from a
single system, while traditional data
warehousing environment is well suited to deal with unstructured data, as well as when a data
discovery process is needed.
D. Traditional data warehousing environments are mostly ideal for analyzing structured data from
various systems, while a Hadoop environment is
well suited to deal with semi-structured and unstructured data, as well as when a data discovery
process is needed.
Answer: D

NEW QUESTION: 2
HOTSPOT
Your network contains an Active Directory domain named contoso.com. The domain contains two member servers named Server1 and Server2. All servers run Windows Server 2012.
Server1 and Server2 have the Hyper-V server role and the Failover Clustering feature installed.
Server1 and Server2 are members of a cluster named Cluster1. Cluster1 hosts 10 virtual machines.
When you try to migrate a running virtual machine from one server to another, you receive the following error message: "There was an error checking for virtual machine compatibility on the target node."
You need to ensure that the virtual machines can be migrated from one node to another.
From which node should you perform the configuration?
To answer, select the appropriate node in the answer area.

Answer:
Explanation:


The Migrate to a physical computer with a different processor version setting ensures that the virtual machine uses only the features of the processor that are available on all versions of a virtualization- capable processor by the same processor manufacturer. It does not provide compatibility between different processor manufacturers.

Note: To enable processor compatibility mode for a virtual machine
Click Start, point to Administrative Tools, and then click Hyper-V Manager.
Select the server running Hyper-V and the desired virtual machine.
If the virtual machine is running, you must shut down the virtual machine to change
the processor compatibility mode setting.
In the Action pane, click Settings, and then click Processor.
Expand Processor, and click Compatibility.
Click Migrate to a physical computer with a different processor, and then click OK.
--- ---

NEW QUESTION: 3
When ospf is forming an adjacency, in which state does the actual exchange of information in the link-state database occur?
A. INIT
B. Exchange
C. Exstart
D. Loading
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Down
This is the first OSPF neighbor state. It means that no information (hellos) has been received from this neighbor, but hello packets can still be sent to the neighbor in this state.
During the fully adjacent neighbor state, if a router doesn't receive hello packet from a neighbor within the RouterDeadInterval time (RouterDeadInterval = 4*HelloInterval by default) or if the manually configured neighbor is being removed from the configuration, then the neighbor state changes from Full to Down.
Attempt
This state is only valid for manually configured neighbors in an NBMA environment. In Attempt state, the router sends unicast hello packets every poll interval to the neighbor, from which hellos have not been received within the dead interval.
Init
This state specifies that the router has received a hello packet from its neighbor, but the receiving router's ID was not included in the hello packet. When a router receives a hello packet from a neighbor, it should list the sender's router ID in its hello packet as an acknowledgment that it received a valid hello packet.
2-Way
This state designates that bi-directional communication has been established between two routers. Bi- directional means that each router has seen the other's hello packet. This state is attained when the router receiving the hello packet sees its own Router ID within the received hello packet's neighbor field. At this state, a router decides whether to become adjacent with this neighbor. On broadcast media and non- broadcast multiaccess networks, a router becomes full only with the designated router (DR) and the backup designated router (BDR); it stays in the 2-way state with all other neighbors. On Point-to-point and Point-to-multipoint networks, a router becomes full with all connected routers.
At the end of this stage, the DR and BDR for broadcast and non-broadcast multi-acess networks are elected. For more information on the DR election process, refer to DR Election.
Note: Receiving a Database Descriptor (DBD) packet from a neighbor in the init state will also a cause a transition to 2-way state.
Exstart
Once the DR and BDR are elected, the actual process of exchanging link state information can start between the routers and their DR and BDR.
In this state, the routers and their DR and BDR establish a master-slave relationship and choose the initial sequence number for adjacency formation. The router with the higher router ID becomes the master and starts the exchange, and as such, is the only router that can increment the sequence number. Note that one would logically conclude that the DR/BDR with the highest router ID will become the master during this process of master-slave relation. Remember that the DR/BDR election might be purely by virtue of a higher priority configured on the router instead of highest router ID. Thus, it is possible that a DR plays the role of slave. And also note that master/slave election is on a per-neighbor basis.
Exchange
In the exchange state, OSPF routers exchange database descriptor (DBD) packets. Database descriptors contain link-state advertisement (LSA) headers only and describe the contents of the entire link-state database. Each DBD packet has a sequence number which can be incremented only by master which is explicitly acknowledged by slave. Routers also send link-state request packets and link-state update packets (which contain the entire LSA) in this state. The contents of the DBD received are compared to the information contained in the routers link-state database to check if new or more current link-state information is available with the neighbor.
Loading
In this state, the actual exchange of link state information occurs. Based on the information provided by the DBDs, routers send link-state request packets. The neighbor then provides the requested link-state information in link-state update packets. During the adjacency, if a router receives an outdated or missing LSA, it requests that LSA by sending a link-state request packet. All link-state update packets are acknowledged.
Full
In this state, routers are fully adjacent with each other. All the router and network LSAs are exchanged and the routers' databases are fully synchronized.
Full is the normal state for an OSPF router. If a router is stuck in another state, it is an indication that there are problems in forming adjacencies. The only exception to this is the 2-way state, which is normal in a broadcast network. Routers achieve the FULL state with their DR and BDR in NBMA/broadcast media and FULL state with every neighbor in the remaining media such as point-to-point and point-to-multipoint.
Note: The DR and BDR that achieve FULL state with every router on the segment will display FULL/ DROTHER when you enter the show ip ospf neighbor command on either a DR or BDR. This simply means that the neighbor is not a DR or BDR, but since the router on which the command was entered is either a DR or BDR, this shows the neighbor as FULL/DROTHER.

NEW QUESTION: 4
Dale has 20 days to complete production of an order for an important customer. The customer wants 96 units of product that may be painted either red or white. The red units can be produced at a rate of 4 per day. The white units, because of a different quality of paint, can be produced at a rate of 7 per day. The materials for the red units cost US $80 each, while the white units cost US $120 each. Dale wants to keep costs at a minimum. What is the constraint that expresses the number of units to be produced?
A. (R/4) + (W+7) 20
B. 4R + 7W = 96
C. 4R + 7W = 20
D. R+W=20
Answer: A
Explanation:
The constraint function that expresses the number of units to be produced is R + W = 96, but that is not one of the answer choices. Another constraint is that the total quantities of red (R) and white (W) units must be produced in 20 or fewer days at a rate of 4 red units per day and 7 white units per day. Thus, the time constraint is (R / 4) + (W + 7) 20.