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NEW QUESTION: 1
다음 중 내부 감사의 특징은 무엇입니까?
A. 내부 감사는 일반적으로 외부 감사보다 기간이 짧습니다.
B. 내부 감사 일정이 조직에 미리 게시되어 있습니다.
C. 내부 감사가 정보 기술 (IT) 부서에 보고
D. 경영진은 내부 감사 결과를 읽고 행동해야 합니다.
Answer: D

NEW QUESTION: 2
Which of the following are advantages of using AWS CodeCommit over hosting your own source code
repository system?
A. No specific restriction on files andbranches
B. Reduction in fees paid over licensing
C. All of the above
D. Reduction in hardware maintenance costs
Answer: C
Explanation:
Explanation
The AWS Documentation mentions the following on CodeCommit
Self-hosted version control systems have many potential drawbacks, including:
Expensive per-developer licensing fees.
High hardware maintenance costs.
High support staffing costs.
Limits on the amount and types of files that can be stored and managed.
Limits on the number of branches, the amount of version history, and other related metadata that can be stored.
For more information on CodeCommit please refer to the below link
* http://docs.aws.amazon.com/codecommit/latest/userguide/wel
come.html

NEW QUESTION: 3
You are a database developer of a Microsoft SQL Server 2012 database.
You are designing a table that will store Customer data from different sources. The table will include a column that contains the CustomerID from the source system and a column that contains the SourceID.
A sample of this data is as shown in the following table.

You need to ensure that the table has no duplicate CustomerID within a SourceID. You also need to ensure that the data in the table is in the order of SourceID and then CustomerID.
Which Transact- SQL statement should you use?
A. CREATE TABLE Customer
(SourceID int NOT NULL PRIMARY KEY CLUSTERED,
CustomerID int NOT NULL UNIQUE,
CustomerName varchar(255) NOT NULL);
B. CREATE TABLE Customer
(SourceID int NOT NULL,
CustomerID int NOT NULL,
CustomerName varchar(255) NOT NULL,
CONSTRAINT PK_Customer PRIMARY KEY CLUSTERED
(SourceID, CustomerID));
C. CREATE TABLE Customer
(SourceID int NOT NULL IDENTITY,
CustomerID int NOT NULL IDENTITY,
CustomerName varchar(255) NOT NULL);
D. CREATE TABLE Customer
(SourceID int NOT NULL,
CustomerID int NOT NULL PRIMARY KEY CLUSTERED,
CustomerName varchar(255) NOT NULL);
Answer: B