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NEW QUESTION: 1
シスコは5段階のクラウド計画を立てています。次のうちどれがフェーズの1つではありませんか。
A. 申請更新
B. クラウドネイティブスタック
C. マルチクラウド管理
D. コンテナと分析
Answer: A
Explanation:
https://www.cisco.com/c/dam/m/en_emear/events/2016/emeardcpc2016/pdfs/day_3/Cisco_s_Clo ud_Strategy-Do

NEW QUESTION: 2

{
"Version": "2012-10-17",
"Statement": [{
"Effect": "Allow",
"Principal": {
"AWS": "arn:aws:iam::12112112:user/test"
},
"Action": [
"s3:GetBucketLocation",
"s3:ListBucket",
"s3:GetObject"
],
"Resource": [
"arn:aws:s3:::testweb"
]
}
]
}

A. Option C
B. Option B
C. Option A
D. Option D
Answer: A
Explanation:
The IAM policy allows to test a user in the account 12112112 to perform:
s3:GetBucketLocation
s3:ListBucket
s3:GetObject
Amazon S3 permissions on the testweb bucket.
Reference: http://docs.aws.amazon.com/AmazonS3/latest/dev/access-policy-language-overview.html

NEW QUESTION: 3
View the exhibit and examine the structure of ORDERSand CUSTOMERStables.

Which INSERT statement should be used to add a row into the ORDERStable for the customer whose CUST_LAST_NAMEis Robertsand CREDIT_LIMITis 600? Assume there exists only one row with CUST_LAST_NAME as Roberts and CREDIT_LIMIT as 600.
INSERT INTO (SELECT o.order_id, o.order_date, o.order_mode, c.customer_id,
A. (SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), order_total)
VALUES (1,'10-mar-2007', 'direct', &&customer_id, 1000);
B. o.order_total
FROM orders o, customers c
WHERE o.customer_id = c.customer_id AND c.cust_last_name='Roberts' AND
c.credit_limit=600)
VALUES (1,'10-mar-2007', 'direct', (SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
INSERT INTO orders (order_id, order_date, order_mode,
C. VALUES (1,'10-mar-2007', 'direct',
(SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
INSERT INTO orders (order_id, order_date, order_mode,
D. (SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND credit_limit=600), order_total)
VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000);
INSERT INTO orders
Answer: C