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NEW QUESTION: 1
You grant the Candidate Advanced Search permission to the Recruiter user type, but recruiters have reported that they are unable to view Advanced Search in the Recruiting Center. What is the cause for this issue? (Choose the best answer.)
A. A List Format Variation has not been assigned to the Recruiter configuration profile.
B. Candidate Quick Search and Specific Search is enabled.
C. The Advanced Search Links setting is not enabled in the user account.
D. The Advanced Search Links setting is not enabled in the Recruiter configuration profile.
E. The Advanced Search Save Query setting is not enabled in the user account.
Answer: A

NEW QUESTION: 2
あなたは10人の開発者のグループのチームリーダーです。各デベロッパーに個別のGoogle Cloudプロジェクトを提供しました。これらのプロジェクトは、さまざまなGoogle Cloudソリューションを試すための個人のサンドボックスとして使用できます。
サンドボックス環境で1か月あたり500ドル以上を費やしている開発者がいる場合は、通知を受け取る必要があります。あなたは何をするべきか？
A. プロジェクトごとに予算を作成し、これらすべての予算について予算アラートを構成します。
B. すべてのサンドボックスプロジェクトに対して単一の請求先アカウントを作成し、BigQuery請求書エクスポートを有効にします。データスタジオダッシュボードを作成して、プロジェクトごとの支出をプロットします。
C. サンドボックスプロジェクトごとに個別の請求先アカウントを作成し、BigQuery請求書エクスポートを有効にします。データスタジオのダッシュボードを作成して、請求先アカウントごとの支出をプロットします。
D. すべてのプロジェクトに単一の予算を作成し、この予算に予算アラートを構成します。
Answer: A

NEW QUESTION: 3
Secure Shell（SSH）を介してOracle Cloud Infrastructure接続でMySQL Enterprise Serverを確立します。
新しいMySQL Enterprise Edition Oracle Cloud Infrastructure（OCI）インスタンスにアクセスする場合、SQLおよびリモート管理にMySQL Enterprise Workbenchを使用します。
MySQLアクセス資格情報に基づいてWorkbenchを正常に構成する2つの方法は何ですか？
A. 最初に秘密鍵をppk形式に変換します。 SSH上のTCP / IP、および作成された秘密鍵、opc-user、MySQLアクセス認証情報に基づいて、MySQL CSインスタンスにアクセスできます。
B. MySQL OCIインスタンスのアクセスポート3306を開きます。MySQL接続の場合、このポートを使用し、さらに、提供されたキーに基づいてSSHに基づくリモート管理を設定します。
C. 最初にMySQLルーターを構成し、それらの設定に基づいて、MySQL CSインスタンスにアクセスします。
D. SSH経由のTCP / IPを構成し、作成された秘密鍵、opc-User、およびMySQLアクセス認証情報に基づいて、MySQL OCIインスタンスにアクセスできます。
Answer: B

NEW QUESTION: 4
Given: interface Pet { }
class Dog implements Pet { }
public class Beagle extends Dog{ }
Which three are valid?
A. Dog d = new Beagle();
B. Pet b = new Pet();
C. Beagle c = new Dog();
D. Pet e = new Beagle();
E. Pet a = new Dog();
F. Dog f = new Pet();
Answer: A,D,E
Explanation:
Incorrect:
Not B, not C: Pet is abstact, cannot be instantiated.
Not F: incompatible type. Required Beagle, found Dog.